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Write a regular expression which catches user $HOME in shellscripting

-1

I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript

My attempt is as follows

#!/bin/bash

function user_input () 

 read -p "Type the path for project1:" user_path

 string1="$HOME"
 echo "$string1"

 if [ "$user_path" = "$string1 

function main() 

user_input


main

Terminal output

Please note first entry is a valid path and other two are invalid paths.

jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home
/ort/home/j/jen
valid path

[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash

command-line bash scripts regex

share|improve this question

asked 1 hour ago

JennyJenny

846

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik
  
  – steeldriver
  1 hour ago
  

  
  
  
  

add a comment | 

-1

I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript

My attempt is as follows

#!/bin/bash

function user_input () 

 read -p "Type the path for project1:" user_path

 string1="$HOME"
 echo "$string1"

 if [ "$user_path" = "$string1 

function main() 

user_input


main

Terminal output

Please note first entry is a valid path and other two are invalid paths.

jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home
/ort/home/j/jen
valid path

[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash

command-line bash scripts regex

share|improve this question

asked 1 hour ago

JennyJenny

846

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Regular expression comparison and string (glob pattern) comparison are different things, with different operators in bash (=~ versus == or =); additionally, =~ is only supported within extended test brackets [[ ... ]] afaik
  
  – steeldriver
  1 hour ago
  

  
  
  
  

add a comment | 

I'd like to write a regex in shellscript which would compare the user input path to user$HOME. Then it would raise an error in case the user input path contains the user $HOME. The home folder normally starts with /ort/home but /ort part is not a must. When I run it always gives a valid path although I clearly enter an invalid path. What am I doing wrong? Thanks. Please refer following link[1] if necessary to see how regex are used in shellscript

My attempt is as follows

#!/bin/bash

function user_input () 

 read -p "Type the path for project1:" user_path

 string1="$HOME"
 echo "$string1"

 if [ "$user_path" = "$string1 

function main() 

user_input


main

Terminal output

Please note first entry is a valid path and other two are invalid paths.

jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home
/ort/home/j/jen
valid path

[1]https://stackoverflow.com/questions/2237080/how-to-compare-strings-in-bash

command-line bash scripts regex

share|improve this question

asked 1 hour ago

JennyJenny

846

#!/bin/bash

function user_input () 

 read -p "Type the path for project1:" user_path

 string1="$HOME"
 echo "$string1"

 if [ "$user_path" = "$string1 

function main() 

user_input


main

jenny@server32:~$ ./test.sh 
Type the path for project1:/scratch/random
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home/j/jen
/ort/home/j/jen
valid path

jenny@server32:~$ ./test.sh 
Type the path for project1:/ort/home
/ort/home/j/jen
valid path

share|improve this question

asked 1 hour ago

JennyJenny

846

share|improve this question

asked 1 hour ago

JennyJenny

846

asked 1 hour ago

JennyJenny

846

asked 1 hour ago

JennyJenny

846

1 Answer
1

active

oldest

votes

2

The case command uses glob wildcards which are pretty easy to work with:

case "$user_path" in
 "$HOME"*) echo "Error: path cannot be in your HOME" ;;
 */home/*) echo "Error: cannot have 'home' in the path" ;;
 *) echo "Thank you, valid path" ;;
esac

share|improve this answer

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! It works smoothly. Jen
  
  – Jenny
  48 mins ago
  

  
  
  
  

add a comment | 

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2

The case command uses glob wildcards which are pretty easy to work with:

case "$user_path" in
 "$HOME"*) echo "Error: path cannot be in your HOME" ;;
 */home/*) echo "Error: cannot have 'home' in the path" ;;
 *) echo "Thank you, valid path" ;;
esac

share|improve this answer

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! It works smoothly. Jen
  
  – Jenny
  48 mins ago
  

  
  
  
  

add a comment | 

2

The case command uses glob wildcards which are pretty easy to work with:

case "$user_path" in
 "$HOME"*) echo "Error: path cannot be in your HOME" ;;
 */home/*) echo "Error: cannot have 'home' in the path" ;;
 *) echo "Thank you, valid path" ;;
esac

share|improve this answer

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! It works smoothly. Jen
  
  – Jenny
  48 mins ago
  

  
  
  
  

add a comment | 

The case command uses glob wildcards which are pretty easy to work with:

case "$user_path" in
 "$HOME"*) echo "Error: path cannot be in your HOME" ;;
 */home/*) echo "Error: cannot have 'home' in the path" ;;
 *) echo "Thank you, valid path" ;;
esac

share|improve this answer

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

case "$user_path" in
 "$HOME"*) echo "Error: path cannot be in your HOME" ;;
 */home/*) echo "Error: cannot have 'home' in the path" ;;
 *) echo "Thank you, valid path" ;;
esac

share|improve this answer

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545

answered 54 mins ago

glenn jackmanglenn jackman

12.7k2545