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how to display number of lines in running shell file
The Next CEO of Stack OverflowPHP, ssh2_exec is not working properlyCan you help me to understand this explanation of shell quoting?shell file opens terminal and run a sequence of commands in specific orderProblems understanding how set worksGrep in bash script won't work properlyHow to get BASH to use * wildcard in command?Bash script to maintain audit trail / log of files accessedWhy do I keep getting error not a valid identifierCan anyone help to create such menu?Can we change the credentials that the adduser command asks when we execute it?
For my assignment i need to display the current number of lines inside of a shell file, below i have implemented the wc -l command inside of my program but instead of displaying the number of lines my shell echo's out the actual command and filename. How would I overcome this?
echo "Hello my name is: Roosevelt Mendieta"
echo "My user name is: $USER"
echo "Todays date and time is: `date`"
echo "This file has: " wc -l mendietaRPgm4.sh "lines of code"
read -p "Please enter any number " number
TIME=2
echo "Your number $number * 2 = $(($number * $TIME))"
command-line bash scripts echo
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
add a comment |
For my assignment i need to display the current number of lines inside of a shell file, below i have implemented the wc -l command inside of my program but instead of displaying the number of lines my shell echo's out the actual command and filename. How would I overcome this?
echo "Hello my name is: Roosevelt Mendieta"
echo "My user name is: $USER"
echo "Todays date and time is: `date`"
echo "This file has: " wc -l mendietaRPgm4.sh "lines of code"
read -p "Please enter any number " number
TIME=2
echo "Your number $number * 2 = $(($number * $TIME))"
command-line bash scripts echo
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
add a comment |
For my assignment i need to display the current number of lines inside of a shell file, below i have implemented the wc -l command inside of my program but instead of displaying the number of lines my shell echo's out the actual command and filename. How would I overcome this?
echo "Hello my name is: Roosevelt Mendieta"
echo "My user name is: $USER"
echo "Todays date and time is: `date`"
echo "This file has: " wc -l mendietaRPgm4.sh "lines of code"
read -p "Please enter any number " number
TIME=2
echo "Your number $number * 2 = $(($number * $TIME))"
command-line bash scripts echo
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
For my assignment i need to display the current number of lines inside of a shell file, below i have implemented the wc -l command inside of my program but instead of displaying the number of lines my shell echo's out the actual command and filename. How would I overcome this?
echo "Hello my name is: Roosevelt Mendieta"
echo "My user name is: $USER"
echo "Todays date and time is: `date`"
echo "This file has: " wc -l mendietaRPgm4.sh "lines of code"
read -p "Please enter any number " number
TIME=2
echo "Your number $number * 2 = $(($number * $TIME))"
command-line bash scripts echo
command-line bash scripts echo
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
asked 4 mins ago
Roosevelt MendietaRoosevelt Mendieta
2514
2514
add a comment |
add a comment |
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