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Replace character with another only if repeated and not part of a word


Only match word outside a HTML statement with a regex“ReplaceWith” & - but only part of itRegExp regular expression find & replace whole words onlyJava regex - parts of wordsRegex match word groups and parts of previously matched word groupsWord replacement using regex if the target word is not a part of another wordreplace after “word” character by character in notepad ++?Why does `word (.(?!another-word))*?` match only a character?Replacing consecutive repeated characters in javareplacing part of a string but the part is very long













6















In Python3, the following code works to replace a string (two or more) of *'s with x's.



import re
re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
# 'Replace this xxx but not this *'


But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)



text = "Don't replace foo*** or **bar, either."
# unmodified text expected


How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?










share|improve this question




























    6















    In Python3, the following code works to replace a string (two or more) of *'s with x's.



    import re
    re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
    # 'Replace this xxx but not this *'


    But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)



    text = "Don't replace foo*** or **bar, either."
    # unmodified text expected


    How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?










    share|improve this question


























      6












      6








      6








      In Python3, the following code works to replace a string (two or more) of *'s with x's.



      import re
      re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
      # 'Replace this xxx but not this *'


      But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)



      text = "Don't replace foo*** or **bar, either."
      # unmodified text expected


      How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?










      share|improve this question
















      In Python3, the following code works to replace a string (two or more) of *'s with x's.



      import re
      re.sub(r'*(?=*)|(?<=*)*', 'x', 'Replace this *** but not this *')
      # 'Replace this xxx but not this *'


      But what if I also want to exempt a string of *'s that are part of a "word" like the following? (I.e. the string is attached to one or more [a-zA-Z] characters.)



      text = "Don't replace foo*** or **bar, either."
      # unmodified text expected


      How do I do this? I can probably match the exempted cases as well and use a replacement function to deal with them, but is there a better way?







      python regex python-3.x






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 3 hours ago









      0m3r

      8,02292554




      8,02292554










      asked 4 hours ago









      bongbangbongbang

      607720




      607720






















          2 Answers
          2






          active

          oldest

          votes


















          7














          regex = r"s*2,[sn]"


          This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)



          Call it maybe like this?



          regex = r"s*2,[sn]"


          def replacer(match):
          return 'x' * len(match.group())

          re.sub(regex, replacer, your_string_here)





          share|improve this answer























          • You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

            – bongbang
            3 hours ago



















          0














          This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.



          regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'





          share|improve this answer






















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            2 Answers
            2






            active

            oldest

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            7














            regex = r"s*2,[sn]"


            This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)



            Call it maybe like this?



            regex = r"s*2,[sn]"


            def replacer(match):
            return 'x' * len(match.group())

            re.sub(regex, replacer, your_string_here)





            share|improve this answer























            • You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

              – bongbang
              3 hours ago
















            7














            regex = r"s*2,[sn]"


            This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)



            Call it maybe like this?



            regex = r"s*2,[sn]"


            def replacer(match):
            return 'x' * len(match.group())

            re.sub(regex, replacer, your_string_here)





            share|improve this answer























            • You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

              – bongbang
              3 hours ago














            7












            7








            7







            regex = r"s*2,[sn]"


            This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)



            Call it maybe like this?



            regex = r"s*2,[sn]"


            def replacer(match):
            return 'x' * len(match.group())

            re.sub(regex, replacer, your_string_here)





            share|improve this answer













            regex = r"s*2,[sn]"


            This matches 2 or more * chars, surrounded by whitespace (or ended with a newline)



            Call it maybe like this?



            regex = r"s*2,[sn]"


            def replacer(match):
            return 'x' * len(match.group())

            re.sub(regex, replacer, your_string_here)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 3 hours ago









            Danielle M.Danielle M.

            2,2051623




            2,2051623












            • You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

              – bongbang
              3 hours ago


















            • You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

              – bongbang
              3 hours ago

















            You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

            – bongbang
            3 hours ago






            You gave me a good idea for the use of the replacer function, but your pattern, by including the spaces in the match, would seem to turn this **** string into this******string, which is not I want. It would also not replace **** this string, which I do want to replace. That said, I now have a solution that works thanks to you. Thank you.

            – bongbang
            3 hours ago














            0














            This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.



            regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'





            share|improve this answer



























              0














              This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.



              regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'





              share|improve this answer

























                0












                0








                0







                This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.



                regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'





                share|improve this answer













                This answer is inspired Danielle M.'s. This pattern below seems to give me what I want. The rest is the same as hers.



                regex = r'(?<![a-zA-Z])*2,(?![a-zA-Z])'






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 3 hours ago









                bongbangbongbang

                607720




                607720



























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