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Averaging over columns while ignoring zero entries


Operations on a List of Vectors (Norm)Compute percentages in a listElegant way to map a function over the columns of an arrayHow to count number of observations/rows within each groupHow can Tally group elements that differ only by a sign together?Creating Average Grid data from Co-ordinate and value dataList manipulation, averaging over lists and fidelityHow to select elements from a list of pairs based on 2nd element of the pairSubtract value from listHow to list ArrayFilter?













5












$begingroup$


I have:



list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 
1, 0, 2, 2, 2, 4, 0


I want to calculate the average but without considering the 0s.



The result should be:



Do[
array = list[[All, i]];
total = Total[array];
cnt = Count[array, 0];
result[[i]] = total/(Length@array - cnt);,
i, 1, Length@result
];

result // N

2., 3., 3., 4., 4., 3., 9.


How can I replace the Do loop?










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Mean /@ DeleteCases[Transpose@list, 0, All]
    $endgroup$
    – MarcoB
    13 hours ago










  • $begingroup$
    Thank you for the solution.
    $endgroup$
    – lio
    13 hours ago











  • $begingroup$
    You’re welcome. I’ve added an answer since this solution works for you
    $endgroup$
    – MarcoB
    13 hours ago







  • 4




    $begingroup$
    I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
    $endgroup$
    – J. M. is computer-less
    13 hours ago










  • $begingroup$
    @J.M. Well, that is clever! Cool trick :-)
    $endgroup$
    – MarcoB
    11 hours ago















5












$begingroup$


I have:



list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 
1, 0, 2, 2, 2, 4, 0


I want to calculate the average but without considering the 0s.



The result should be:



Do[
array = list[[All, i]];
total = Total[array];
cnt = Count[array, 0];
result[[i]] = total/(Length@array - cnt);,
i, 1, Length@result
];

result // N

2., 3., 3., 4., 4., 3., 9.


How can I replace the Do loop?










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Mean /@ DeleteCases[Transpose@list, 0, All]
    $endgroup$
    – MarcoB
    13 hours ago










  • $begingroup$
    Thank you for the solution.
    $endgroup$
    – lio
    13 hours ago











  • $begingroup$
    You’re welcome. I’ve added an answer since this solution works for you
    $endgroup$
    – MarcoB
    13 hours ago







  • 4




    $begingroup$
    I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
    $endgroup$
    – J. M. is computer-less
    13 hours ago










  • $begingroup$
    @J.M. Well, that is clever! Cool trick :-)
    $endgroup$
    – MarcoB
    11 hours ago













5












5








5





$begingroup$


I have:



list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 
1, 0, 2, 2, 2, 4, 0


I want to calculate the average but without considering the 0s.



The result should be:



Do[
array = list[[All, i]];
total = Total[array];
cnt = Count[array, 0];
result[[i]] = total/(Length@array - cnt);,
i, 1, Length@result
];

result // N

2., 3., 3., 4., 4., 3., 9.


How can I replace the Do loop?










share|improve this question











$endgroup$




I have:



list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 
1, 0, 2, 2, 2, 4, 0


I want to calculate the average but without considering the 0s.



The result should be:



Do[
array = list[[All, i]];
total = Total[array];
cnt = Count[array, 0];
result[[i]] = total/(Length@array - cnt);,
i, 1, Length@result
];

result // N

2., 3., 3., 4., 4., 3., 9.


How can I replace the Do loop?







list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 hours ago









m_goldberg

87.4k872198




87.4k872198










asked 14 hours ago









liolio

1,108217




1,108217







  • 1




    $begingroup$
    Mean /@ DeleteCases[Transpose@list, 0, All]
    $endgroup$
    – MarcoB
    13 hours ago










  • $begingroup$
    Thank you for the solution.
    $endgroup$
    – lio
    13 hours ago











  • $begingroup$
    You’re welcome. I’ve added an answer since this solution works for you
    $endgroup$
    – MarcoB
    13 hours ago







  • 4




    $begingroup$
    I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
    $endgroup$
    – J. M. is computer-less
    13 hours ago










  • $begingroup$
    @J.M. Well, that is clever! Cool trick :-)
    $endgroup$
    – MarcoB
    11 hours ago












  • 1




    $begingroup$
    Mean /@ DeleteCases[Transpose@list, 0, All]
    $endgroup$
    – MarcoB
    13 hours ago










  • $begingroup$
    Thank you for the solution.
    $endgroup$
    – lio
    13 hours ago











  • $begingroup$
    You’re welcome. I’ve added an answer since this solution works for you
    $endgroup$
    – MarcoB
    13 hours ago







  • 4




    $begingroup$
    I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
    $endgroup$
    – J. M. is computer-less
    13 hours ago










  • $begingroup$
    @J.M. Well, that is clever! Cool trick :-)
    $endgroup$
    – MarcoB
    11 hours ago







1




1




$begingroup$
Mean /@ DeleteCases[Transpose@list, 0, All]
$endgroup$
– MarcoB
13 hours ago




$begingroup$
Mean /@ DeleteCases[Transpose@list, 0, All]
$endgroup$
– MarcoB
13 hours ago












$begingroup$
Thank you for the solution.
$endgroup$
– lio
13 hours ago





$begingroup$
Thank you for the solution.
$endgroup$
– lio
13 hours ago













$begingroup$
You’re welcome. I’ve added an answer since this solution works for you
$endgroup$
– MarcoB
13 hours ago





$begingroup$
You’re welcome. I’ve added an answer since this solution works for you
$endgroup$
– MarcoB
13 hours ago





4




4




$begingroup$
I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
$endgroup$
– J. M. is computer-less
13 hours ago




$begingroup$
I'm not at a computer right now, so please try Total[list]/Total[Unitize[list]].
$endgroup$
– J. M. is computer-less
13 hours ago












$begingroup$
@J.M. Well, that is clever! Cool trick :-)
$endgroup$
– MarcoB
11 hours ago




$begingroup$
@J.M. Well, that is clever! Cool trick :-)
$endgroup$
– MarcoB
11 hours ago










2 Answers
2






active

oldest

votes


















8












$begingroup$

Mean /@ DeleteCases[Transpose@list, 0, All]



2,3,3,4,4,3,9







share|improve this answer









$endgroup$




















    7












    $begingroup$

    I'm posting this as a CW answer, so J.M.'s very nice answer, made in a comment above, gets recorded as a real answer.



    list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 1, 0, 2, 2, 2, 4, 0;
    Total[list]/Total[Unitize[list]]



    2, 3, 3, 4, 4, 3, 9







    share|improve this answer











    $endgroup$












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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      8












      $begingroup$

      Mean /@ DeleteCases[Transpose@list, 0, All]



      2,3,3,4,4,3,9







      share|improve this answer









      $endgroup$

















        8












        $begingroup$

        Mean /@ DeleteCases[Transpose@list, 0, All]



        2,3,3,4,4,3,9







        share|improve this answer









        $endgroup$















          8












          8








          8





          $begingroup$

          Mean /@ DeleteCases[Transpose@list, 0, All]



          2,3,3,4,4,3,9







          share|improve this answer









          $endgroup$



          Mean /@ DeleteCases[Transpose@list, 0, All]



          2,3,3,4,4,3,9








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 13 hours ago









          MarcoBMarcoB

          37.2k556113




          37.2k556113





















              7












              $begingroup$

              I'm posting this as a CW answer, so J.M.'s very nice answer, made in a comment above, gets recorded as a real answer.



              list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 1, 0, 2, 2, 2, 4, 0;
              Total[list]/Total[Unitize[list]]



              2, 3, 3, 4, 4, 3, 9







              share|improve this answer











              $endgroup$

















                7












                $begingroup$

                I'm posting this as a CW answer, so J.M.'s very nice answer, made in a comment above, gets recorded as a real answer.



                list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 1, 0, 2, 2, 2, 4, 0;
                Total[list]/Total[Unitize[list]]



                2, 3, 3, 4, 4, 3, 9







                share|improve this answer











                $endgroup$















                  7












                  7








                  7





                  $begingroup$

                  I'm posting this as a CW answer, so J.M.'s very nice answer, made in a comment above, gets recorded as a real answer.



                  list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 1, 0, 2, 2, 2, 4, 0;
                  Total[list]/Total[Unitize[list]]



                  2, 3, 3, 4, 4, 3, 9







                  share|improve this answer











                  $endgroup$



                  I'm posting this as a CW answer, so J.M.'s very nice answer, made in a comment above, gets recorded as a real answer.



                  list = 1, 3, 4, 5, 6, 0, 9, 4, 0, 3, 5, 0, 2, 0, 1, 0, 2, 2, 2, 4, 0;
                  Total[list]/Total[Unitize[list]]



                  2, 3, 3, 4, 4, 3, 9








                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  answered 11 hours ago


























                  community wiki





                  m_goldberg




























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