Can I feed enough spin up electron to a black hole to affect it's angular momentum? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) 2019 Moderator Election Q&A - Question CollectionIs Angular Momentum truly fundamental?How can a particle with no size have angular momentum?Why can't I just think the spin as rotating?What is the significance of electron spin quantum number?What all has intrinsic spin?Is the conservation of angular momentum violated in electron jumps from one orbital to another?Relationship Between Magnetic Dipole Moment and Spin Angular MomentumWhat is the angular momentum of an electron? And how can it be zero?Interpretation of rotating a quantum stateOrbital angular momentum quantum numbers - subtracted?
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Can I feed enough spin up electron to a black hole to affect it's angular momentum?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
2019 Moderator Election Q&A - Question CollectionIs Angular Momentum truly fundamental?How can a particle with no size have angular momentum?Why can't I just think the spin as rotating?What is the significance of electron spin quantum number?What all has intrinsic spin?Is the conservation of angular momentum violated in electron jumps from one orbital to another?Relationship Between Magnetic Dipole Moment and Spin Angular MomentumWhat is the angular momentum of an electron? And how can it be zero?Interpretation of rotating a quantum stateOrbital angular momentum quantum numbers - subtracted?
$begingroup$
I was reading classical spin vs quantum field spin, I know spin in quantum mechanics is just a quantum number but what happens of I try to intentionally feed many electrons all in the same spin state into a rotating 5 solar mass blackhole, can I affect it's angular momentum eventually?
black-holes angular-momentum electrons conservation-laws quantum-spin
edited 1 hour ago
Qmechanic♦
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
$endgroup$
add a comment |
$begingroup$
I was reading classical spin vs quantum field spin, I know spin in quantum mechanics is just a quantum number but what happens of I try to intentionally feed many electrons all in the same spin state into a rotating 5 solar mass blackhole, can I affect it's angular momentum eventually?
black-holes angular-momentum electrons conservation-laws quantum-spin
edited 1 hour ago
Qmechanic♦
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
$endgroup$
add a comment |
$begingroup$
I was reading classical spin vs quantum field spin, I know spin in quantum mechanics is just a quantum number but what happens of I try to intentionally feed many electrons all in the same spin state into a rotating 5 solar mass blackhole, can I affect it's angular momentum eventually?
black-holes angular-momentum electrons conservation-laws quantum-spin
edited 1 hour ago
Qmechanic♦
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
$endgroup$
I was reading classical spin vs quantum field spin, I know spin in quantum mechanics is just a quantum number but what happens of I try to intentionally feed many electrons all in the same spin state into a rotating 5 solar mass blackhole, can I affect it's angular momentum eventually?
black-holes angular-momentum electrons conservation-laws quantum-spin
black-holes angular-momentum electrons conservation-laws quantum-spin
edited 1 hour ago
Qmechanic♦
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
edited 1 hour ago
Qmechanic♦
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
edited 1 hour ago
Qmechanic♦
108k122001252
edited 1 hour ago
Qmechanic♦
108k122001252
edited 1 hour ago
Qmechanic♦
108k122001252
108k122001252
asked 2 hours ago
user6760user6760
3,14112144
asked 2 hours ago
user6760user6760
3,14112144
asked 2 hours ago
user6760user6760
3,14112144
3,14112144
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I infer that you are asking whether spin angular momentum can accumulate to a macroscopically significant amount.
It is generally claimed that spin angular momentum does not have a classical counterpart. So maybe there is no connection with macroscopic angular momentum at all?
About the black hole in your thought experiment: my guess is that you added that element to the picture because nothing escapes a black hole. That is, the fact that the electrons enter a black hole ensures that it is a one way trip.
Check out this youtube video titled Einstein De Haas effect, uploaded by the University of Michigan Demo lab
The demo shows a torsion pendulum.
The amplitude of the swing is back and forth around a vertical axis. The amplitude of the swing increases because the swing is pumped. The current in the surrounding coil is reversed in resonance with the natural frequency of the torsion pendulum. The Einstein De Haas effect is very small, the resonance setup accumulates the effect to a significant amplitude.
The particular metal in the setup, presumably iron, has a significant population of electrons with a spin that can be reoriented by an external magnetic field. Every time the current is reversed the direction of the magnetic field is reversed, and the alignable electrons realign. But angular momentum cannot change, so the electrons must exchange angular momentum with external mass.
I find the Einstein De Haas effect fascinating: you get to see a quantum effect accumulate to a level where you see a physical consequence with the unaided eye.
answered 1 hour ago
CleonisCleonis
2,363714
$endgroup$
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
add a comment |
$begingroup$
A single electron will already alter the angular momentum of a black hole by exactly $hbar/2$.
answered 2 hours ago
my2ctsmy2cts
5,9042719
$endgroup$
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I infer that you are asking whether spin angular momentum can accumulate to a macroscopically significant amount.
It is generally claimed that spin angular momentum does not have a classical counterpart. So maybe there is no connection with macroscopic angular momentum at all?
About the black hole in your thought experiment: my guess is that you added that element to the picture because nothing escapes a black hole. That is, the fact that the electrons enter a black hole ensures that it is a one way trip.
Check out this youtube video titled Einstein De Haas effect, uploaded by the University of Michigan Demo lab
The demo shows a torsion pendulum.
The amplitude of the swing is back and forth around a vertical axis. The amplitude of the swing increases because the swing is pumped. The current in the surrounding coil is reversed in resonance with the natural frequency of the torsion pendulum. The Einstein De Haas effect is very small, the resonance setup accumulates the effect to a significant amplitude.
The particular metal in the setup, presumably iron, has a significant population of electrons with a spin that can be reoriented by an external magnetic field. Every time the current is reversed the direction of the magnetic field is reversed, and the alignable electrons realign. But angular momentum cannot change, so the electrons must exchange angular momentum with external mass.
I find the Einstein De Haas effect fascinating: you get to see a quantum effect accumulate to a level where you see a physical consequence with the unaided eye.
answered 1 hour ago
CleonisCleonis
2,363714
$endgroup$
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
add a comment |
$begingroup$
I infer that you are asking whether spin angular momentum can accumulate to a macroscopically significant amount.
It is generally claimed that spin angular momentum does not have a classical counterpart. So maybe there is no connection with macroscopic angular momentum at all?
About the black hole in your thought experiment: my guess is that you added that element to the picture because nothing escapes a black hole. That is, the fact that the electrons enter a black hole ensures that it is a one way trip.
Check out this youtube video titled Einstein De Haas effect, uploaded by the University of Michigan Demo lab
The demo shows a torsion pendulum.
The amplitude of the swing is back and forth around a vertical axis. The amplitude of the swing increases because the swing is pumped. The current in the surrounding coil is reversed in resonance with the natural frequency of the torsion pendulum. The Einstein De Haas effect is very small, the resonance setup accumulates the effect to a significant amplitude.
The particular metal in the setup, presumably iron, has a significant population of electrons with a spin that can be reoriented by an external magnetic field. Every time the current is reversed the direction of the magnetic field is reversed, and the alignable electrons realign. But angular momentum cannot change, so the electrons must exchange angular momentum with external mass.
I find the Einstein De Haas effect fascinating: you get to see a quantum effect accumulate to a level where you see a physical consequence with the unaided eye.
answered 1 hour ago
CleonisCleonis
2,363714
$endgroup$
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
add a comment |
$begingroup$
I infer that you are asking whether spin angular momentum can accumulate to a macroscopically significant amount.
It is generally claimed that spin angular momentum does not have a classical counterpart. So maybe there is no connection with macroscopic angular momentum at all?
About the black hole in your thought experiment: my guess is that you added that element to the picture because nothing escapes a black hole. That is, the fact that the electrons enter a black hole ensures that it is a one way trip.
Check out this youtube video titled Einstein De Haas effect, uploaded by the University of Michigan Demo lab
The demo shows a torsion pendulum.
The amplitude of the swing is back and forth around a vertical axis. The amplitude of the swing increases because the swing is pumped. The current in the surrounding coil is reversed in resonance with the natural frequency of the torsion pendulum. The Einstein De Haas effect is very small, the resonance setup accumulates the effect to a significant amplitude.
The particular metal in the setup, presumably iron, has a significant population of electrons with a spin that can be reoriented by an external magnetic field. Every time the current is reversed the direction of the magnetic field is reversed, and the alignable electrons realign. But angular momentum cannot change, so the electrons must exchange angular momentum with external mass.
I find the Einstein De Haas effect fascinating: you get to see a quantum effect accumulate to a level where you see a physical consequence with the unaided eye.
answered 1 hour ago
CleonisCleonis
2,363714
$endgroup$
I infer that you are asking whether spin angular momentum can accumulate to a macroscopically significant amount.
It is generally claimed that spin angular momentum does not have a classical counterpart. So maybe there is no connection with macroscopic angular momentum at all?
About the black hole in your thought experiment: my guess is that you added that element to the picture because nothing escapes a black hole. That is, the fact that the electrons enter a black hole ensures that it is a one way trip.
Check out this youtube video titled Einstein De Haas effect, uploaded by the University of Michigan Demo lab
The demo shows a torsion pendulum.
The amplitude of the swing is back and forth around a vertical axis. The amplitude of the swing increases because the swing is pumped. The current in the surrounding coil is reversed in resonance with the natural frequency of the torsion pendulum. The Einstein De Haas effect is very small, the resonance setup accumulates the effect to a significant amplitude.
The particular metal in the setup, presumably iron, has a significant population of electrons with a spin that can be reoriented by an external magnetic field. Every time the current is reversed the direction of the magnetic field is reversed, and the alignable electrons realign. But angular momentum cannot change, so the electrons must exchange angular momentum with external mass.
I find the Einstein De Haas effect fascinating: you get to see a quantum effect accumulate to a level where you see a physical consequence with the unaided eye.
answered 1 hour ago
CleonisCleonis
2,363714
answered 1 hour ago
CleonisCleonis
2,363714
answered 1 hour ago
CleonisCleonis
2,363714
answered 1 hour ago
CleonisCleonis
2,363714
2,363714
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
add a comment |
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
$begingroup$
I'm puzzled why you say "So maybe there is no connection with macroscopic angular momentum at all?" Intrinsic angular momentum is genuine, honest-to-goodness angular momentum, and the Einstein-De Haas effect demonstrates that. Sure, spin has no classical counterpart because in a classical composite spinning body all of its angular momentum is due to the orbital angular momenta of its components. But I suppose if you had a spinning body made of a continuous substance (no atoms), then the substance at the exact axis has intrinsic spin.
$endgroup$
– PM 2Ring
23 mins ago
add a comment |
$begingroup$
A single electron will already alter the angular momentum of a black hole by exactly $hbar/2$.
answered 2 hours ago
my2ctsmy2cts
5,9042719
$endgroup$
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
add a comment |
$begingroup$
A single electron will already alter the angular momentum of a black hole by exactly $hbar/2$.
answered 2 hours ago
my2ctsmy2cts
5,9042719
$endgroup$
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
add a comment |
$begingroup$
A single electron will already alter the angular momentum of a black hole by exactly $hbar/2$.
answered 2 hours ago
my2ctsmy2cts
5,9042719
$endgroup$
A single electron will already alter the angular momentum of a black hole by exactly $hbar/2$.
answered 2 hours ago
my2ctsmy2cts
5,9042719
edited 38 mins ago
answered 2 hours ago
my2ctsmy2cts
5,9042719
answered 2 hours ago
my2ctsmy2cts
5,9042719
answered 2 hours ago
my2ctsmy2cts
5,9042719
5,9042719
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
add a comment |
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
1
1
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
You mean $hbar/2$.
$endgroup$
– G. Smith
45 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
$begingroup$
@G. Smith Indeed, thanks
$endgroup$
– my2cts
37 mins ago
add a comment |
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