draw a pulley system Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them

Table formatting with tabularx?

Determine whether an integer is a palindrome

How many time has Arya actually used Needle?

How to make an animal which can only breed for a certain number of generations?

Is there night in Alpha Complex?

What does 丫 mean? 丫是什么意思?

How can I list files in reverse time order by a command and pass them as arguments to another command?

Does the universe have a fixed centre of mass?

Does a random sequence of vectors span a Hilbert space?

Weaponising the Grasp-at-a-Distance spell

Was the pager message from Nick Fury to Captain Marvel unnecessary?

The Nth Gryphon Number

How can I prevent/balance waiting and turtling as a response to cooldown mechanics

Why did Bronn offer to be Tyrion Lannister's champion in trial by combat?

What is "Lambda" in Heston's original paper on stochastic volatility models?

Do i imagine the linear (straight line) homotopy in a correct way?

Can I cut the hair of a conjured korred with a blade made of precious material to harvest that material from the korred?

Keep at all times, the minus sign above aligned with minus sign below

IC on Digikey is 5x more expensive than board containing same IC on Alibaba: How?

Shimano 105 brifters (5800) and Avid BB5 compatibility

First paper to introduce the "principal-agent problem"

How to infer difference of population proportion between two groups when proportion is small?

Is the time—manner—place ordering of adverbials an oversimplification?

draw a pulley system



draw a pulley system



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them










1















enter image description here
I need to draw a pulley system as in the figure. Can you help?



 begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);

draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);

draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;

draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);

draw[fill=white] (0,-3) circle (.153);


endtikzpicture









share|improve this question




























    1















    enter image description here
    I need to draw a pulley system as in the figure. Can you help?



     begintikzpicture
    fill[pattern=north east lines] (-3,0) rectangle (3,.3);
    draw(-3,0)--(3,0);
    draw(-2.5,0)--(-2.5,-2.4);
    draw(2.5,0)--(2.5,-1);

    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);
    draw[fill=white] (0,-3) circle (.153);

    draw
    (2.5,-1) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (0,-2.75) coordinate (c) node[above right]
    pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
    angle=a--b--c;

    draw
    (0,-2.75) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (-2.5,-2.4) coordinate (c) node[above right]
    pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
    angle=a--b--c;
    draw[dashed] (0,-3)--(0,-1);
    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);

    draw[fill=white] (0,-3) circle (.153);


    endtikzpicture









    share|improve this question


























      1












      1








      1


      0






      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture









      share|improve this question
















      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture






      tikz-pgf






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago







      Thumbolt

















      asked 2 hours ago









      ThumboltThumbolt

      1,516822




      1,516822




















          1 Answer
          1






          active

          oldest

          votes


















          3














          In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



          documentclass[tikz,border=3.14mm]standalone
          usetikzlibrarypatterns,calc,angles,quotes
          begindocument
          begintikzpicture
          fill[pattern=north east lines] (-3,0) rectangle (3,.3);
          beginscope[thick]
          draw(-3,0)--(3,0);

          path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
          (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
          (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
          draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
          draw[dashed] (M) -- (0,-1)coordinate (M1);
          draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
          let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
          draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
          let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
          endscope
          path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
          pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
          endtikzpicture
          enddocument


          enter image description here






          share|improve this answer

























            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "85"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



            documentclass[tikz,border=3.14mm]standalone
            usetikzlibrarypatterns,calc,angles,quotes
            begindocument
            begintikzpicture
            fill[pattern=north east lines] (-3,0) rectangle (3,.3);
            beginscope[thick]
            draw(-3,0)--(3,0);

            path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
            (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
            (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
            draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
            draw[dashed] (M) -- (0,-1)coordinate (M1);
            draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
            let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
            draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
            let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
            endscope
            path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
            pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer





























              3














              In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



              documentclass[tikz,border=3.14mm]standalone
              usetikzlibrarypatterns,calc,angles,quotes
              begindocument
              begintikzpicture
              fill[pattern=north east lines] (-3,0) rectangle (3,.3);
              beginscope[thick]
              draw(-3,0)--(3,0);

              path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
              (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
              (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
              draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
              draw[dashed] (M) -- (0,-1)coordinate (M1);
              draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
              let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
              draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
              let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
              endscope
              path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
              pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer



























                3












                3








                3







                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here






                share|improve this answer















                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 1 hour ago

























                answered 2 hours ago









                marmotmarmot

                120k6156292




                120k6156292



























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Möglingen Índice Localización Historia Demografía Referencias Enlaces externos Menú de navegación48°53′18″N 9°07′45″E / 48.888333333333, 9.129166666666748°53′18″N 9°07′45″E / 48.888333333333, 9.1291666666667Sitio web oficial Mapa de Möglingen«Gemeinden in Deutschland nach Fläche, Bevölkerung und Postleitzahl am 30.09.2016»Möglingen

                    Virtualbox - Configuration error: Querying “UUID” failed (VERR_CFGM_VALUE_NOT_FOUND)“VERR_SUPLIB_WORLD_WRITABLE” error when trying to installing OS in virtualboxVirtual Box Kernel errorFailed to open a seesion for the virtual machineFailed to open a session for the virtual machineUbuntu 14.04 LTS Virtualbox errorcan't use VM VirtualBoxusing virtualboxI can't run Linux-64 Bit on VirtualBoxUnable to insert the virtual optical disk (VBoxguestaddition) in virtual machine for ubuntu server in win 10VirtuaBox in Ubuntu 18.04 Issues with Win10.ISO Installation

                    Torre de la Isleta Índice Véase también Referencias Bibliografía Enlaces externos Menú de navegación38°25′58″N 0°23′02″O / 38.43277778, -0.3838888938°25′58″N 0°23′02″O / 38.43277778, -0.38388889Torre de la Illeta de l’Horta o Torre Saleta. Base de datos de bienes inmuebles. Patrimonio Cultural. Secretaría de Estado de CulturaFicha BIC Torre de la Illeta de l’Horta. Dirección General de Patrimonio Cultural. Generalitat ValencianaLugares de interés. Ayuntamiento del CampelloTorre de la Isleta en CastillosNet.org