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STM32 programming and BOOT0 pin



The 2019 Stack Overflow Developer Survey Results Are InSTM32F102 USB ProgrammingSTM32F303RET's core is always halted after programmingST-Link debugger/programmer failed to find STM32L152 MCU on designed PCBSTM32 prototype unable to connect to PC using ST-Link/V2 SWDSTM32 'Connect under reset' suddenly stopped workingCannot Program a Custom STM32 BoardWhy is this hex file different than the code programmed onto the device?STM32F091 Jump to Bootloader from applicationSTM32 & ST-LINK - SWD connector not workingSTM32F0 - interrupt/breakpoint not working on certain hardware



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


I am developing a STM32H7 board which will be programmed via SWD.



I am curious, is there any reason why I should connect BOOT0 pin to GND via resistor and not directly to GND?



I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?










share|improve this question









$endgroup$











  • $begingroup$
    if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
    $endgroup$
    – jsotola
    49 mins ago

















1












$begingroup$


I am developing a STM32H7 board which will be programmed via SWD.



I am curious, is there any reason why I should connect BOOT0 pin to GND via resistor and not directly to GND?



I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?










share|improve this question









$endgroup$











  • $begingroup$
    if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
    $endgroup$
    – jsotola
    49 mins ago













1












1








1





$begingroup$


I am developing a STM32H7 board which will be programmed via SWD.



I am curious, is there any reason why I should connect BOOT0 pin to GND via resistor and not directly to GND?



I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?










share|improve this question









$endgroup$




I am developing a STM32H7 board which will be programmed via SWD.



I am curious, is there any reason why I should connect BOOT0 pin to GND via resistor and not directly to GND?



I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?







stm32 bootloader






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 4 hours ago









ningboningbo

243




243











  • $begingroup$
    if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
    $endgroup$
    – jsotola
    49 mins ago
















  • $begingroup$
    if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
    $endgroup$
    – jsotola
    49 mins ago















$begingroup$
if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
$endgroup$
– jsotola
49 mins ago




$begingroup$
if you have a resistor to ground, then you can change the state of the pin by connecting it to Vcc ... if the pin is connected to ground directly, then you have to disconnect it before it can be pulled high
$endgroup$
– jsotola
49 mins ago










2 Answers
2






active

oldest

votes


















2












$begingroup$

If you're making a board, why not provide for a resistor/jumper to connect Boot0 to +V and GND? Then only populate one of them? Leave your options open. You don't need a resistor. I prefer to use a jumper rather than a resistor.



You can use header shunts as jumpers that can be easily changed but that takes more PCB space, components and more assembly work. Or just place an SMD chip footprint you can either choose to use an SMD resistor or SMD jumper (zero ohm resistor) during assembly. Then you can fiddle with things all you want after-the-fact.






share|improve this answer











$endgroup$




















    2












    $begingroup$


    I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?




    That's exactly why you might want to use a resistor and not a zero ohm jumper. With a resistor, you can manually override it with a piece of wire to the opposite rail start in bootloader mode once, without having to get out the hot air station and change the resistor.



    Granted, if you have the hardware reset line brought out, and an SWD probe that actually drives it, and a suitable SWD software config (both common points of failure - and specifically a failure that may not be noticed in routine use, but only when this kind of recovery fails to work) then that is another way to work around disabled SWD lines.






    share|improve this answer









    $endgroup$













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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      If you're making a board, why not provide for a resistor/jumper to connect Boot0 to +V and GND? Then only populate one of them? Leave your options open. You don't need a resistor. I prefer to use a jumper rather than a resistor.



      You can use header shunts as jumpers that can be easily changed but that takes more PCB space, components and more assembly work. Or just place an SMD chip footprint you can either choose to use an SMD resistor or SMD jumper (zero ohm resistor) during assembly. Then you can fiddle with things all you want after-the-fact.






      share|improve this answer











      $endgroup$

















        2












        $begingroup$

        If you're making a board, why not provide for a resistor/jumper to connect Boot0 to +V and GND? Then only populate one of them? Leave your options open. You don't need a resistor. I prefer to use a jumper rather than a resistor.



        You can use header shunts as jumpers that can be easily changed but that takes more PCB space, components and more assembly work. Or just place an SMD chip footprint you can either choose to use an SMD resistor or SMD jumper (zero ohm resistor) during assembly. Then you can fiddle with things all you want after-the-fact.






        share|improve this answer











        $endgroup$















          2












          2








          2





          $begingroup$

          If you're making a board, why not provide for a resistor/jumper to connect Boot0 to +V and GND? Then only populate one of them? Leave your options open. You don't need a resistor. I prefer to use a jumper rather than a resistor.



          You can use header shunts as jumpers that can be easily changed but that takes more PCB space, components and more assembly work. Or just place an SMD chip footprint you can either choose to use an SMD resistor or SMD jumper (zero ohm resistor) during assembly. Then you can fiddle with things all you want after-the-fact.






          share|improve this answer











          $endgroup$



          If you're making a board, why not provide for a resistor/jumper to connect Boot0 to +V and GND? Then only populate one of them? Leave your options open. You don't need a resistor. I prefer to use a jumper rather than a resistor.



          You can use header shunts as jumpers that can be easily changed but that takes more PCB space, components and more assembly work. Or just place an SMD chip footprint you can either choose to use an SMD resistor or SMD jumper (zero ohm resistor) during assembly. Then you can fiddle with things all you want after-the-fact.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago

























          answered 4 hours ago









          ToorToor

          1,527210




          1,527210























              2












              $begingroup$


              I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?




              That's exactly why you might want to use a resistor and not a zero ohm jumper. With a resistor, you can manually override it with a piece of wire to the opposite rail start in bootloader mode once, without having to get out the hot air station and change the resistor.



              Granted, if you have the hardware reset line brought out, and an SWD probe that actually drives it, and a suitable SWD software config (both common points of failure - and specifically a failure that may not be noticed in routine use, but only when this kind of recovery fails to work) then that is another way to work around disabled SWD lines.






              share|improve this answer









              $endgroup$

















                2












                $begingroup$


                I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?




                That's exactly why you might want to use a resistor and not a zero ohm jumper. With a resistor, you can manually override it with a piece of wire to the opposite rail start in bootloader mode once, without having to get out the hot air station and change the resistor.



                Granted, if you have the hardware reset line brought out, and an SWD probe that actually drives it, and a suitable SWD software config (both common points of failure - and specifically a failure that may not be noticed in routine use, but only when this kind of recovery fails to work) then that is another way to work around disabled SWD lines.






                share|improve this answer









                $endgroup$















                  2












                  2








                  2





                  $begingroup$


                  I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?




                  That's exactly why you might want to use a resistor and not a zero ohm jumper. With a resistor, you can manually override it with a piece of wire to the opposite rail start in bootloader mode once, without having to get out the hot air station and change the resistor.



                  Granted, if you have the hardware reset line brought out, and an SWD probe that actually drives it, and a suitable SWD software config (both common points of failure - and specifically a failure that may not be noticed in routine use, but only when this kind of recovery fails to work) then that is another way to work around disabled SWD lines.






                  share|improve this answer









                  $endgroup$




                  I won't be using the bootloader but can it happen that I accidentally disable the debug port from software and then can't program the MCU via SWD anymore and need to use bootloader mode by putting BOOT0 high?




                  That's exactly why you might want to use a resistor and not a zero ohm jumper. With a resistor, you can manually override it with a piece of wire to the opposite rail start in bootloader mode once, without having to get out the hot air station and change the resistor.



                  Granted, if you have the hardware reset line brought out, and an SWD probe that actually drives it, and a suitable SWD software config (both common points of failure - and specifically a failure that may not be noticed in routine use, but only when this kind of recovery fails to work) then that is another way to work around disabled SWD lines.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 3 hours ago









                  Chris StrattonChris Stratton

                  23.2k22865




                  23.2k22865



























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