Eliminate empty elements from a list with a specific patternList operation on specific elementsSelect elements from list with given headSelecting elements from a list with nullsReplace empty list elements with patternReplacing Non-Constant Elements from List with Patternselecting elements from a list with two numbersRemoving elements of a specific length from a listEliminate types of elements from the listListPlot3D with empty matrix elementsDelete a large pattern from one list

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Eliminate empty elements from a list with a specific pattern


List operation on specific elementsSelect elements from list with given headSelecting elements from a list with nullsReplace empty list elements with patternReplacing Non-Constant Elements from List with Patternselecting elements from a list with two numbersRemoving elements of a specific length from a listEliminate types of elements from the listListPlot3D with empty matrix elementsDelete a large pattern from one list













3












$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    12 hours ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    11 hours ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    11 hours ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    11 hours ago















3












$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    12 hours ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    11 hours ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    11 hours ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    11 hours ago













3












3








3


1



$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$




I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.







list-manipulation filtering






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago









Roman

4,66511128




4,66511128










asked 12 hours ago









morsmors

496




496











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    12 hours ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    11 hours ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    11 hours ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    11 hours ago
















  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    12 hours ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    11 hours ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    11 hours ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    11 hours ago















$begingroup$
Have a look at DeleteCases and StringMatchQ or StringContainsQ.
$endgroup$
– b.gatessucks
12 hours ago




$begingroup$
Have a look at DeleteCases and StringMatchQ or StringContainsQ.
$endgroup$
– b.gatessucks
12 hours ago












$begingroup$
I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
$endgroup$
– Roman
11 hours ago





$begingroup$
I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
$endgroup$
– Roman
11 hours ago













$begingroup$
@b.gatessucks Thank you, I will look those option in Mathematica.
$endgroup$
– mors
11 hours ago




$begingroup$
@b.gatessucks Thank you, I will look those option in Mathematica.
$endgroup$
– mors
11 hours ago












$begingroup$
@Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
$endgroup$
– mors
11 hours ago




$begingroup$
@Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
$endgroup$
– mors
11 hours ago










2 Answers
2






active

oldest

votes


















7












$begingroup$

If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
Select[list, Not@*StringMatchQ[__ ~~ ""]]



"a12-b11-1", "d33-c22-2"




You could also Select before making the strings:



L = DeleteCases[
Flatten[
Table[
namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
i, 4, j, 4],
1],
_, _, ];


and then make these into strings:



StringRiffle[ToString /@ #, "-"] & /@ L


I can't check this because you didn't supply functioning code.






share|improve this answer











$endgroup$












  • $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    12 hours ago



















0












$begingroup$

In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
Select[list, Not@*StringEndsQ[""]]


instead.






share|improve this answer









$endgroup$













    Your Answer





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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$












    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      12 hours ago
















    7












    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$












    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      12 hours ago














    7












    7








    7





    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$



    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 8 hours ago

























    answered 12 hours ago









    RomanRoman

    4,66511128




    4,66511128











    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      12 hours ago

















    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      12 hours ago
















    $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    12 hours ago





    $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    12 hours ago












    0












    $begingroup$

    In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringEndsQ[""]]


    instead.






    share|improve this answer









    $endgroup$

















      0












      $begingroup$

      In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



      list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
      Select[list, Not@*StringEndsQ[""]]


      instead.






      share|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



        list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
        Select[list, Not@*StringEndsQ[""]]


        instead.






        share|improve this answer









        $endgroup$



        In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



        list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
        Select[list, Not@*StringEndsQ[""]]


        instead.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 6 hours ago









        rcollyerrcollyer

        28.6k674166




        28.6k674166



























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