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Jenkins list user ids using script console
User script at logoutIs there a startup shell script for Jenkins?new user from text file scriptscript convert files using dos2unixHow to read user last email using a shell script?logout current user from scriptCannot activate python virtual env in jenkins shell scriptHow to run Perl script in jenkinsRandom script using bashcannot run jenkins build job as another user
I want to list all users in jenkins, via the console script that jenkins has.
So far i managed to list all the users using this:
import hudson.model.User
User.getAll().each user ->
println user
but they are listed by the first and last name, which i don't need...
I would like to list them by their user IDs, can you give me a hand? I looked thru their documentation but i fail to understand how to use it the right way. I m not so experimented with groovy scripting..
Any ideas? Thank you!
scripts console jenkins groovy
add a comment |
I want to list all users in jenkins, via the console script that jenkins has.
So far i managed to list all the users using this:
import hudson.model.User
User.getAll().each user ->
println user
but they are listed by the first and last name, which i don't need...
I would like to list them by their user IDs, can you give me a hand? I looked thru their documentation but i fail to understand how to use it the right way. I m not so experimented with groovy scripting..
Any ideas? Thank you!
scripts console jenkins groovy
add a comment |
I want to list all users in jenkins, via the console script that jenkins has.
So far i managed to list all the users using this:
import hudson.model.User
User.getAll().each user ->
println user
but they are listed by the first and last name, which i don't need...
I would like to list them by their user IDs, can you give me a hand? I looked thru their documentation but i fail to understand how to use it the right way. I m not so experimented with groovy scripting..
Any ideas? Thank you!
scripts console jenkins groovy
I want to list all users in jenkins, via the console script that jenkins has.
So far i managed to list all the users using this:
import hudson.model.User
User.getAll().each user ->
println user
but they are listed by the first and last name, which i don't need...
I would like to list them by their user IDs, can you give me a hand? I looked thru their documentation but i fail to understand how to use it the right way. I m not so experimented with groovy scripting..
Any ideas? Thank you!
scripts console jenkins groovy
scripts console jenkins groovy
edited 3 hours ago
yash
1053
1053
asked Aug 14 '18 at 6:48
Caranfil AlegzandruCaranfil Alegzandru
1492312
1492312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
According to the hudson.modle.User documentation, you can use the getId() method to get the user's id.
Probably like that:
import hudson.model.User
User.getAll().each user ->
println user.getId()
add a comment |
First, sorry for posting this on ask ubuntu instead of serverfault.
I found the perfect way:
import hudson.model.User
import jenkins.model.Jenkins
def realm = Jenkins.getInstance().getSecurityRealm()
def users = realm.getAllUsers()
for (User u : users)
def userid = u.getId()
println(userid + " ")
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
According to the hudson.modle.User documentation, you can use the getId() method to get the user's id.
Probably like that:
import hudson.model.User
User.getAll().each user ->
println user.getId()
add a comment |
According to the hudson.modle.User documentation, you can use the getId() method to get the user's id.
Probably like that:
import hudson.model.User
User.getAll().each user ->
println user.getId()
add a comment |
According to the hudson.modle.User documentation, you can use the getId() method to get the user's id.
Probably like that:
import hudson.model.User
User.getAll().each user ->
println user.getId()
According to the hudson.modle.User documentation, you can use the getId() method to get the user's id.
Probably like that:
import hudson.model.User
User.getAll().each user ->
println user.getId()
answered Aug 14 '18 at 8:43
pimpim
1,9391925
1,9391925
add a comment |
add a comment |
First, sorry for posting this on ask ubuntu instead of serverfault.
I found the perfect way:
import hudson.model.User
import jenkins.model.Jenkins
def realm = Jenkins.getInstance().getSecurityRealm()
def users = realm.getAllUsers()
for (User u : users)
def userid = u.getId()
println(userid + " ")
add a comment |
First, sorry for posting this on ask ubuntu instead of serverfault.
I found the perfect way:
import hudson.model.User
import jenkins.model.Jenkins
def realm = Jenkins.getInstance().getSecurityRealm()
def users = realm.getAllUsers()
for (User u : users)
def userid = u.getId()
println(userid + " ")
add a comment |
First, sorry for posting this on ask ubuntu instead of serverfault.
I found the perfect way:
import hudson.model.User
import jenkins.model.Jenkins
def realm = Jenkins.getInstance().getSecurityRealm()
def users = realm.getAllUsers()
for (User u : users)
def userid = u.getId()
println(userid + " ")
First, sorry for posting this on ask ubuntu instead of serverfault.
I found the perfect way:
import hudson.model.User
import jenkins.model.Jenkins
def realm = Jenkins.getInstance().getSecurityRealm()
def users = realm.getAllUsers()
for (User u : users)
def userid = u.getId()
println(userid + " ")
edited 3 hours ago
yash
1053
1053
answered Aug 14 '18 at 9:02
Caranfil AlegzandruCaranfil Alegzandru
1492312
1492312
add a comment |
add a comment |
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